Bresenham's Line Algorithm

Bresenham's Line Algorithm is a way of drawing a line segment onto a square grid. It is especially useful for roguelikes due to their cellular nature.

In libtcod it is accessible using line(x1, y1, x2, y2, callback). Below are several hand-coded implementations in various languages.

C#

Here is a simple way of using the algorithm in C# with delegates.

using System;

namespace Bresenhams
{
    /// <summary>
    /// The Bresenham algorithm collection
    /// </summary>
    public static class Algorithms
    {
        private static void Swap<T>(ref T lhs, ref T rhs) { T temp; temp = lhs; lhs = rhs; rhs = temp; }

        /// <summary>
        /// The plot function delegate
        /// </summary>
        /// <param name="x">The x co-ord being plotted</param>
        /// <param name="y">The y co-ord being plotted</param>
        /// <returns>True to continue, false to stop the algorithm</returns>
        public delegate bool PlotFunction(int x, int y);

        /// <summary>
        /// Plot the line from (x0, y0) to (x1, y10
        /// </summary>
        /// <param name="x0">The start x</param>
        /// <param name="y0">The start y</param>
        /// <param name="x1">The end x</param>
        /// <param name="y1">The end y</param>
        /// <param name="plot">The plotting function (if this returns false, the algorithm stops early)</param>
        public static void Line(int x0, int y0, int x1, int y1, PlotFunction plot)
        {
            bool steep = Math.Abs(y1 - y0) > Math.Abs(x1 - x0);
            if (steep) { Swap<int>(ref x0, ref y0); Swap<int>(ref x1, ref y1); }
            if (x0 > x1) { Swap<int>(ref x0, ref x1); Swap<int>(ref y0, ref y1); }
            int dX = (x1 - x0), dY = (y1 - y0), err = (dX / 2), ystep = (y0 < y1 ? 1 : -1), y = y0;

            for (int x = x0; x <= x1; ++x)
            {
                if (!(steep ? plot(y, x) : plot(x, y))) return;
                err = err - dY;
                if (err < 0) { y += ystep;  err += dX; }
            }
        }
    }
}

C++

Here's a C++ version; plot() draws a "dot" at (x, y):

////////////////////////////////////////////////////////////////////////////////
void Bresenham(int x1,
    int y1,
    int x2,
    int y2)
{
    signed char ix;
    signed char iy;

    // if x1 == x2 or y1 == y2, then it does not matter what we set here
    int delta_x = (x2 > x1?(ix = 1, x2 - x1):(ix = -1, x1 - x2)) << 1;
    int delta_y = (y2 > y1?(iy = 1, y2 - y1):(iy = -1, y1 - y2)) << 1;

    plot(x1, y1);

    if (delta_x >= delta_y)
    {
        // error may go below zero
        int error = delta_y - (delta_x >> 1);
 
        while (x1 != x2)
        {
            if (error >= 0)
            {
                if (error || (ix > 0))
                {
                    y1 += iy;
                    error -= delta_x;
                }
                // else do nothing
            }
            // else do nothing

            x1 += ix;
            error += delta_y;

            plot(x1, y1);
        }
    }
    else
    {
        // error may go below zero
        int error = delta_x - (delta_y >> 1);

        while (y1 != y2)
        {
            if (error >= 0)
            {
                if (error || (iy > 0))
                {
                    x1 += ix;
                    error -= delta_y;
                }
                // else do nothing
            }
            // else do nothing

            y1 += iy;
            error += delta_x;
 
            plot(x1, y1);
        }
    }
}

Ruby

Here's a Ruby version, it returns an array of points, each being a hash with 2 elements (x and y).

def get_line(x0,x1,y0,y1)
  points = []
  steep = ((y1-y0).abs) > ((x1-x0).abs)
  if steep
    x0,y0 = y0,x0
    x1,y1 = y1,x1
  end
  if x0 > x1
    x0,x1 = x1,x0
    y0,y1 = y1,y0
  end
  deltax = x1-x0
  deltay = (y1-y0).abs
  error = (deltax / 2).to_i
  y = y0
  ystep = nil
  if y0 < y1
    ystep = 1
  else
    ystep = -1
  end
  for x in x0..x1
    if steep
      points << {:x => y, :y => x}
    else
      points << {:x => x, :y => y}
    end
    error -= deltay
    if error < 0
      y += ystep
      error += deltax
    end
  end
  return points
end

VB.NET

Here is a generic way of using the algorithm in VB.NET using delegates.

Module BresenhamsLineAlgorithm
    Sub Swap(ByRef X As Long, ByRef Y As Long)
        Dim t As Long = X
        X = Y
        Y = t
    End Sub
    ' If the plot function returns true, the bresenham's line algorithm continues.
    ' if the plot function returns false, the algorithm stops
    Delegate Function PlotFunction(ByVal x As Long, ByVal y As Long) As Boolean
    Sub Bresenham(ByVal x1 As Long, ByVal y1 As Long, ByVal x2 As Long, ByVal y2 As Long, ByVal plot As PlotFunction)
        Dim steep As Boolean = (Math.Abs(y2 - y1) > Math.Abs(x2 - x1))
        If (steep) Then
            Swap(x1, y1)
            Swap(x2, y2)
        End If
        If (x1 > x2) Then
            Swap(x1, x2)
            Swap(y1, y2)
        End If
        Dim deltaX As Long = x2 - x1
        Dim deltaY As Long = y2 - y1
        Dim err As Long = deltaX / 2
        Dim ystep As Long
        Dim y As Long = y1
        If (y1 < y2) Then
            ystep = 1
        Else
            ystep = -1
       End If
       For x As Long = x1 To x2
            Dim result As Boolean
            If (steep) Then result = plot(y, x) Else result = plot(x, y)
            If (Not result) Then Exit Sub
            err = err - deltaY
            If (err < 0) Then
                y = y + ystep
                err = err + deltaX
            End If
       Next
    End Sub
    Function plot(ByVal x As Long, ByVal y As Long) As Boolean
        Console.WriteLine(x.ToString() + " " + y.ToString())
        Return True 'This just prints each co-ord
    End Function
    Sub Main()
        ' example
        Bresenham(1, 1, 10, 15, New PlotFunction(AddressOf plot))
        Console.ReadLine()
    End Sub
End Module